Passing References to const
Why should I pass references to const when a function does not modify its arguments?
Passing references to const is a best practice in C++ for several reasons:
- It clearly communicates to other developers that the function will not modify the argument.
- It allows the function to accept both non-const and const arguments. If you don't use
const, you can only pass non-const arguments. - It can avoid unnecessary copying of large objects, which can improve performance.
Here's an example:
#include <iostream>
struct Vector {
float x;
float y;
float z;
};
void PrintVector(const Vector& v) {
std::cout << "Vector: (" << v.x << ", "
<< v.y << ", " << v.z << ")\n";
}
int main() {
const Vector v1{1, 2, 3};
Vector v2{4, 5, 6};
PrintVector(v1); // Okay, v1 is const
PrintVector(v2); // Also okay, v2 is non-const
}Vector: (1, 2, 3)
Vector: (4, 5, 6)If PrintVector didn't use const, it couldn't accept v1 as an argument.
Understanding Reference and Pointer Types
Learn the fundamentals of references, pointers, and the const keyword in C++ programming.