How Template Argument Deduction Works
Fixing "no matching function call" errors when using function templates.
Template argument deduction is the process by which the compiler determines the template arguments based on the types of the function arguments. Here's how it works:
- The compiler compares the types of the function arguments with the types of the function parameters in the template.
- If the types match exactly, the corresponding template argument is deduced.
- If the function argument is a reference or pointer, the compiler will try to deduce the template argument based on the referred or pointed-to type.
- If the function argument is a const or volatile qualifier, the compiler will attempt to deduce the template argument by removing the qualifiers.
- If the template has default arguments, they will be used if no corresponding function argument is provided.
- If the compiler cannot deduce all template arguments or if there are conflicts, a compilation error occurs.
Example:
template <typename T>
void foo(T a, T b) {
// ...
}
int main() {
int x = 10;
double y = 5.5;
foo(x, x);// T is deduced as int
foo(y, 2.3);// T is deduced as double
// Compilation error - cannot deduce T
// because the arguments have different types
foo(x, y);
}
We can fix this by providing our template arguments, or casting our function arguments to help the compiler deduce how to instantiate the template:
foo<int, int>(x, y);
foo(int(x), int(y));
Function Templates
Understand the fundamentals of C++ function templates and harness generics for more modular, adaptable code.