Value Categories (L-Values and R-Values)

std::move vs static_cast<T&&>

What are the differences between using std::move and static_cast<T&&> for casting to r-value references?

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Both std::move and static_cast<T&&> can be used to cast an object to an r-value reference, enabling move semantics. However, there are some differences between the two:

Readability and intent

  • std::move is a standard library function that is specifically designed to indicate the intent of moving an object. It makes the code more readable and expressive by explicitly conveying the purpose of the operation.
  • static_cast<T&&> is a general-purpose casting operator that can be used for various type conversions. When used for casting to an r-value reference, it may not be immediately clear to the reader that the intent is to enable move semantics.

Type deduction

  • std::move uses type deduction to determine the appropriate r-value reference type based on the argument passed to it. It automatically deduces the type T and returns an r-value reference of type T&&.
  • With static_cast<T&&>, you need to explicitly specify the type T to which you want to cast the object. This can be more verbose and potentially error-prone if the type is complex or subject to change.

Consistency with standard library

  • std::move is part of the standard library and is widely used in C++ codebases. It provides a consistent and idiomatic way to express the intent of moving objects.
  • Using static_cast<T&&> for moving objects, while functionally equivalent, may not be as common or immediately recognizable to other developers familiar with the standard library conventions.

Here's an example illustrating the usage of both std::move and static_cast<T&&>:

#include <iostream>
#include <utility>

class MyClass {
  MyClass() {
    std::cout << "Default constructor\n";
  MyClass(const MyClass&) {
    std::cout << "Copy constructor\n";
  MyClass(MyClass&&) {
    std::cout << "Move constructor\n";

void AcceptRvalueRef(MyClass&& obj) {
  MyClass newObj(std::move(obj));  

int main() {
  MyClass obj;
Default constructor
Move constructor
Move constructor

In this example, both std::move(obj) and static_cast<MyClass&&>(obj) achieve the same result of casting obj to an r-value reference, enabling the move constructor to be called.

However, the use of std::move is generally preferred because it clearly expresses the intent of moving the object and is more idiomatic in modern C++ code.

Answers to questions are automatically generated and may not have been reviewed.

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