Using splice_after() in std::forward_list
How can I transfer elements from one forward_list to another using splice_after()?
The splice_after() member function in std::forward_list allows you to transfer elements from one list to another in constant time. It comes in three forms:
Splicing a single element:
#include <forward_list>
#include <iostream>
int main() {
std::forward_list<int> list1{1, 2, 3};
std::forward_list<int> list2{4, 5, 6};
auto it = list1.begin();
list1.splice_after(it, list2, list2.begin());
std::cout << "List 1: ";
for (auto i : list1) {
std::cout << i << ", ";
}
std::cout << "\nList 2: ";
for (auto i : list2) {
std::cout << i << ", ";
}
}List 1: 1, 5, 2, 3,
List 2: 4, 6,Splicing a range of elements:
#include <forward_list>
#include <iostream>
int main() {
std::forward_list<int> list1{1, 2, 3};
std::forward_list<int> list2{4, 5, 6, 7};
auto it = list1.begin();
list1.splice_after(it, list2, list2.begin(),
std::next(list2.begin(), 2));
std::cout << "List 1: ";
for (auto i : list1) {
std::cout << i << ", ";
}
std::cout << "\nList 2: ";
for (auto i : list2) {
std::cout << i << ", ";
}
}List 1: 1, 5, 2, 3,
List 2: 4, 6, 7,Splicing an entire list:
#include <forward_list>
#include <iostream>
int main() {
std::forward_list<int> list1{1, 2};
std::forward_list<int> list2{3, 4, 5};
list1.splice_after(list1.before_begin(),
list2);
std::cout << "List 1: ";
for (auto i : list1) {
std::cout << i << ", ";
}
std::cout << "\nList 2: ";
for (auto i : list2) {
std::cout << i << ", ";
}
}List 1: 3, 4, 5, 1, 2,
List 2:Note that the elements are inserted after the given position. The source list is left empty if the entire list is spliced.
Linked Lists using std::forward_list
This lesson provides an in-depth exploration of std::forward_list, covering creation, management, and advanced list operations