Yes, a functor class can contain non-operator member functions, just like any other class. These functions can be called using the dot notation on an instance of theÂ functor.

Here's an example of a functor with a regular memberÂ function:

```
#include <iostream>
class Functor {
public:
void operator()() const {
std::cout << "Calling operator()\n";
}
void SayHello() const {
std::cout << "Hello from Functor!\n";
}
};
int main() {
Functor f;
f(); // Call operator()
f.SayHello(); // Call SayHello()
}
```

```
Calling operator()
Hello from Functor!
```

You can also call non-operator member functions on a temporary functorÂ instance:

```
#include <iostream>
class Functor {
public:
void SayHello() const {
std::cout << "Hello from Functor!\n";
}
};
int main() {
Functor().SayHello();
}
```

`Hello from Functor!`

This creates a temporary `Functor`

object, calls `SayHello()`

on it, and then immediately destroys the temporaryÂ object.

Non-operator member functions in functors can be useful for providing additional functionality related to the callable, such as setting up state or returning information about the functor's currentÂ state.

Answers to questions are automatically generated and may not have been reviewed.

This Question is from the Lesson:### Function Objects (Functors)

This lesson introduces function objects, or functors. This concept allows us to create objects that can be used as functions, including state management and parameter handling.