Return Types in Function Try Blocks

When using a function try block, you specify the return type of the function before the try keyword, just like in a regular function. Here's an example:

1#include <stdexcept>
2
3int divideNumbers(int a, int b) try {
4  if (b == 0) {
5    throw std::invalid_argument{
6      "Division by zero"};
7  }
8  return a / b;
9} catch (const std::exception& e) {
10  // Handle the exception
11  return -1;
12}

In this example, the divideNumbers function has a return type of int. The return type is specified before the try keyword.

Inside the function try block, if a division by zero is attempted, an exception is thrown. The catch block catches the exception and returns a value of -1 to indicate an error.

It's important to note that all the catch blocks in a function try block must return a value that is compatible with the function's return type. In this case, both the normal return statement (return a / b;) and the return statement in the catch block (return -1;) return an int value.

If the function has a void return type, then the catch blocks should not return any value.

1#include <iostream>
2#include <stdexcept>
3
4void printValue(int value) try {
5  if (value < 0) {
6    throw std::invalid_argument{"Negative value"};
7  }
8  std::cout << "Value: " << value << "\n";
9} catch (const std::exception& e) {
10  std::cout << "Exception: " << e.what() << "\n";
11  // No return statement needed for void functions
12}

In this example, the printValue function has a void return type, so the catch block does not return any value.