List Initialization with constexpr and constinit

How does list initialization interact with constexpr and constinit specifiers in C++20?

List initialization works well with constexpr and constinit specifiers, enhancing compile-time evaluation and constant initialization in C++20.

These specifiers help ensure that variables are initialized at compile-time, leading to safer and more efficient code.

constexpr

The constexpr specifier indicates that the value of a variable or function can be evaluated at compile-time. You can use list initialization with constexpr to define compile-time constants:

#include <iostream>

struct Vec3 {
  int x, y, z;
};

constexpr Vec3 CreateVector(int a, int b, int c) {
  return {a, b, c};  
}

int main() {
  constexpr Vec3 vector = CreateVector(1, 2, 3);  
  std::cout << "x=" << vector.x
    << ", y=" << vector.y
    << ", z=" << vector.z;
}
x=1, y=2, z=3

In this example, the CreateVector function is constexpr, meaning it can be evaluated at compile-time. The vector variable is also constexpr, ensuring its value is determined during compilation.

constinit

The constinit specifier, introduced in C++20, guarantees that a variable is initialized at compile-time. Unlike constexpr, constinit can be used with non-constant expressions, as long as the initialization happens at compile-time:

#include <iostream>

struct Vec3 {
  int x, y, z;
};

constinit Vec3 vector = {1, 2, 3};  

int main() {
  std::cout << "x=" << vector.x
    << ", y=" << vector.y
    << ", z=" << vector.z;
}
x=1, y=2, z=3

Here, constinit ensures that vector is initialized at compile-time. If the initialization expression were not a constant expression, the code would not compile.

Combining constexpr and List Initialization

You can combine constexpr with list initialization to create complex compile-time constants:

#include <iostream>

struct Vec3 {
  int x, y, z;
};

struct Transform {
  Vec3 position;
  Vec3 rotation;
  Vec3 scale;
};

constexpr Transform CreateTransform() {
  return {{0, 0, 0}, {0, 0, 0}, {1, 1, 1}};  
}

int main() {
  constexpr Transform transform = CreateTransform();
  std::cout
    << "Position: x=" << transform.position.x
    << ", y=" << transform.position.y
    << ", z=" << transform.position.z;
}
Position: x=0, y=0, z=0

This example demonstrates a Transform structure initialized using list initialization within a constexpr function. The resulting transform variable is a compile-time constant.

In summary, list initialization interacts seamlessly with constexpr and constinit, enabling efficient and safe compile-time initialization of variables and constants.

Using these specifiers, you can ensure that your variables are initialized correctly and efficiently, leveraging the full power of compile-time evaluation in C++20.

List, Aggregate, and Designated Initialization

A quick guide to creating objects using lists, including std::initializer_list, aggregate and designated initialization

Questions & Answers

Answers are generated by AI models and may not have been reviewed. Be mindful when running any code on your device.

List Initialization with Private Members
Can we use list initialization for classes with private or protected members?
Aggregate Initialization for Nested Structures
How does aggregate initialization work for complex types with nested structures?
Using Initializer Lists in Custom Containers
How can we use std::initializer_list to initialize custom container types?
Designated Initializers with Private Members
Can designated initializers be used with types that have private or protected members?
Aggregate Initialization with Inheritance
How does aggregate initialization interact with inheritance and derived classes?
Heterogeneous Initializer Lists
Can std::initializer_list be used with heterogeneous data types in any way?
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