Trailing Return Types and auto

How do trailing return types relate to the auto keyword in C++?

Trailing return types and auto are closely related when defining functions. When you use a trailing return type, you must use auto in place of the actual return type before the function name. For example:

auto Add(int x, int y) -> int {
  return x + y;
}

Here, auto essentially acts as a placeholder, indicating that the actual return type will be specified after the parameter list using the -> syntax.

This is different from using auto without a trailing return type:

auto Subtract(int x, int y) {
  return x - y;
}

In this case, auto tells the compiler to deduce the return type from the return statement. The function will return an int, but that type isn't explicitly specified in the function signature.

So in summary:

  • auto with a trailing return type: the auto is a placeholder and the actual type is specified after the ->
  • auto without a trailing return type: auto tells the compiler to deduce the return type

Trailing Return Types

An alternative syntax for defining function templates, which allows the return type to be based on their parameter types

Questions & Answers

Answers are generated by AI models and may not have been reviewed. Be mindful when running any code on your device.

When to Use Trailing Return Types in C++
In what situations is it beneficial or necessary to use trailing return types in C++ functions?
Using decltype with Trailing Return Types
How can I use decltype in combination with trailing return types?
Trailing Return Types and Function Qualifiers
How do I use trailing return types with const, override, or final qualifiers?
Advantages of Trailing Return Types
Apart from template functions, what are some other advantages of using trailing return types in C++?
Best Practices for Trailing Return Types
What are some best practices to follow when using trailing return types in C++?
Or Ask your Own Question
Get an immediate answer to your specific question using our AI assistant