Using std::is_base_of with Template Types
How can I use std::is_base_of to check if a template type is derived from a specific base class?
To use std::is_base_of with a template type, you can pass the base class and the template type as the template arguments to std::is_base_of. Here's an example:
#include <iostream>
#include <type_traits>
class BaseClass {};
class DerivedClass : public BaseClass {};
template <typename T>
void checkDerived() {
if constexpr (std::is_base_of_v<BaseClass, T>) {
std::cout << "T is derived from BaseClass\n";
} else {
std::cout << "T is not derived from BaseClass";
}
}
int main() {
// Output: T is derived from BaseClass
checkDerived<DerivedClass>();
// Output: T is not derived from BaseClass
checkDerived<int>();
}T is derived from BaseClass
T is not derived from BaseClassIn this example, the checkDerived function uses std::is_base_of_v to check if the template type T is derived from BaseClass. The if constexpr statement allows conditional compilation based on the result of the type trait.
Type Traits: Compile-Time Type Analysis
Learn how to use type traits to perform compile-time type analysis, enable conditional compilation, and enforce type requirements in templates.