When multiple elements in a container match the search value, binary search alone won't suffice to find allÂ occurrences.

Instead, you should use `std::ranges::lower_bound()`

and `std::ranges::upper_bound()`

to identify the range of matchingÂ elements.

`lower_bound()`

`upper_bound()`

`std::ranges::lower_bound()`

finds the first position where the element could be inserted, and `std::ranges::upper_bound()`

finds the lastÂ position.

Here's an example demonstrating how to find the range of elements equal to a specificÂ value:

```
#include <algorithm>
#include <iostream>
#include <vector>
int main() {
std::vector<int> Nums{1, 2, 3, 4, 4, 4, 5};
int target = 4;
auto lower = std::ranges::lower_bound(
Nums, target);
auto upper = std::ranges::upper_bound(
Nums, target);
if (lower != Nums.end() && *lower == target) {
std::cout << "Range of " << target << ": [";
for (auto it = lower; it != upper; ++it) {
std::cout << *it
<< (it + 1 != upper ? ", " : "");
}
std::cout << "]";
} else {
std::cout << "Element not found";
}
}
```

`Range of 4: [4, 4, 4]`

**Efficiency**: Using`lower_bound()`

and`upper_bound()`

together is efficient, with both operations being $O(log n)$.**Exact Range**: You get the exact range of matching elements, which is useful for further processing.

You can count the number of occurrences of a value by finding the distance between `lower_bound()`

and `upper_bound()`

:

```
#include <algorithm>
#include <iostream>
#include <vector>
int main() {
std::vector<int> Numbers{1, 2, 3, 4, 4, 4, 5};
int target = 4;
auto lower = std::ranges::lower_bound(
Numbers, target);
auto upper = std::ranges::upper_bound(
Numbers, target);
int count = std::distance(lower, upper);
std::cout << "Count of " << target << ": "
<< count;
}
```

`Count of 4: 3`

Always check if the `lower_bound()`

result is within the container and matches the target value before using the range. This avoids incorrect results when the value is notÂ present.

```
#include <algorithm>
#include <iostream>
#include <vector>
int main() {
std::vector<int> Nums{1, 2, 3, 4, 4, 4, 5};
int target = 6;
auto lower = std::ranges::lower_bound(
Nums, target);
auto upper = std::ranges::upper_bound(
Nums, target);
if (lower != Nums.end() && *lower == target) {
int count = std::distance(lower, upper);
std::cout << "Count of " << target
<< ": " << count;
} else {
std::cout << "Element not found";
}
}
```

`Element not found`

Using `std::ranges::lower_bound()`

and `std::ranges::upper_bound()`

allows you to efficiently handle multiple matches in a sortedÂ container.

These functions provide the exact range of matching elements, making it easy to perform further operations like counting or iterating through theÂ matches.

Answers to questions are automatically generated and may not have been reviewed.

This Question is from the Lesson:### Binary Search in C++

An introduction to the advantages of binary search, and how to use it with the C++ standard library algorithms `binary_search()`

, `lower_bound()`

, `upper_bound()`

, and `equal_range()`