Implementing a custom type conversion in C++ that converts an object to a built-in type involves overloading a typecast operator within your class.
This operator defines how the conversion should be performed. Here’s a step-by-step guide using an example:
Complex
Number to double
Let’s implement a custom type conversion for a Complex
number class that converts the object to a double
representing its magnitude.
#include <iostream>
#include <cmath>
class Complex {
public:
double real, imag;
Complex(double r, double i)
: real(r), imag(i) {}
// Overload the double typecast operator
operator double() const {
return std::sqrt(real * real + imag * imag);
}
};
int main() {
Complex num(3.0, 4.0);
// Convert Complex to double
double magnitude = num;
std::cout << "Magnitude: " << magnitude;
}
Magnitude: 5
Complex
class has two members, real
and imag
, representing the real and imaginary parts of the complex number.operator double()
function calculates the magnitude of the complex number using the formula and returns it as a double
.In the main()
function, we create a Complex
object and then convert it to a double
by simply assigning it to a double
variable. The compiler calls the operator double()
function to perform the conversion.
explicit
keyword if you want to prevent implicit conversions.By following these steps, you can implement custom type conversions that integrate your custom types smoothly with C++'s built-in types, enhancing the usability and expressiveness of your code.
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Learn how to add conversion functions to our classes, so our custom objects can be converted to other types.